(2-3x^2)(x^3+8)=0

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Solution for (2-3x^2)(x^3+8)=0 equation: 


Simplifying
(2 + -3x2)(x3 + 8) = 0

Reorder the terms:
(2 + -3x2)(8 + x3) = 0

Multiply (2 + -3x2) * (8 + x3)
(2(8 + x3) + -3x2 * (8 + x3)) = 0
((8 * 2 + x3 * 2) + -3x2 * (8 + x3)) = 0
((16 + 2x3) + -3x2 * (8 + x3)) = 0
(16 + 2x3 + (8 * -3x2 + x3 * -3x2)) = 0
(16 + 2x3 + (-24x2 + -3x5)) = 0

Reorder the terms:
(16 + -24x2 + 2x3 + -3x5) = 0
(16 + -24x2 + 2x3 + -3x5) = 0

Solving
16 + -24x2 + 2x3 + -3x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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